{"id":1739,"date":"2018-01-11T14:40:38","date_gmt":"2018-01-11T11:40:38","guid":{"rendered":"http:\/\/mekanikelektriktesisat.com\/?p=1739"},"modified":"2018-01-11T14:40:38","modified_gmt":"2018-01-11T11:40:38","slug":"dengesiz-uc-fazli-sistemler","status":"publish","type":"post","link":"https:\/\/benga.pro\/index.php\/2018\/01\/11\/dengesiz-uc-fazli-sistemler\/","title":{"rendered":"Dengesiz \u00dc\u00e7 Fazl\u0131 Sistemler"},"content":{"rendered":"

N\u00d6TR HATTI BULUNMAYAN YILDIZ BA\u011eLI \u015eEBEKEN\u0130N ANAL\u0130Z\u0130<\/strong><\/h4>\n

 <\/p>\n

\"res1\"<\/p>\n

ZL1<\/sub>, ZL2,<\/sub> ZL3\u00a0\u00a0 <\/sub>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 L1, L2 ve L3 fazlar\u0131n\u0131n toplam empedanslar\u0131<\/p>\n

ZhL1<\/sub> , ZhL2<\/sub> , ZhL3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>L1, L2, ve L3 hatlar\u0131n\u0131n (besleme kablolar\u0131n\u0131n) empedanslar\u0131<\/p>\n

ZYL1<\/sub> , ZYL2<\/sub> , ZYL3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>L1, L2, ve L3 hatlar\u0131ndan beslenen y\u00fcklerin empedanslar\u0131<\/p>\n

Uo<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>Toprak gerilimi, 0 V<\/p>\n

UN<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>N\u00f6tr noktas\u0131 ile toprak aras\u0131 gerilim<\/p>\n

UL1<\/sub> , UL2<\/sub> ,UL3<\/sub>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 L1, L2 ve L3 hatlar\u0131 ile toprak aras\u0131 gerilimleri<\/p>\n

IL1<\/sub> , IL2<\/sub>, IL3<\/sub>\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>L1, L2 ve L3 hatlar\u0131 y\u00fck ak\u0131mlar\u0131<\/p>\n

 <\/p>\n

\u00d6ncelikle seri halde bulunan besleme hatt\u0131 empedanslar\u0131 ile y\u00fck empedanslar\u0131n\u0131 toplayarak faz ba\u015f\u0131na gelen toplam empedanslar\u0131 bularak form\u00fclleri basitle\u015ftirelim.<\/p>\n\n\n\n\n\n
ZL1<\/sub>=ZhL1<\/sub> + ZYL1<\/sub><\/td>\n1<\/td>\n<\/tr>\n
ZL2<\/sub>=ZhL2<\/sub> + ZYL2<\/sub><\/td>\n2<\/td>\n<\/tr>\n
ZL3<\/sub>=ZhL3<\/sub> + ZYL3<\/sub><\/td>\n3<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

N\u00f6tr noktas\u0131 N d\u00fc\u011f\u00fcm\u00fcne gelen ve \u00e7\u0131kan ak\u0131mlar\u0131n toplamlar\u0131 e\u015fit olacakt\u0131r. Ancak n\u00f6tr noktas\u0131nda herhangi bir topraklama yap\u0131lmad\u0131\u011f\u0131ndan \u00e7\u0131kan ak\u0131m bulunmamaktad\u0131r ve haliyle a\u015fa\u011f\u0131daki e\u015fitlik olu\u015fmaktad\u0131r.<\/p>\n\n\n\n
IL1<\/sub> + IL2 <\/sub>+ IL3<\/sub>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 = 0<\/td>\n4<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Her bir ak\u0131m de\u011feri i\u00e7in ohm kanununa g\u00f6re d\u00f6n\u00fc\u015f\u00fcm yapar ve i\u015flemleri sadele\u015ftirirsek:<\/p>\n

\"formul1\"<\/p>\n

UN <\/sub>\u00a0\u00a0gerilim de\u011feri i\u00e7in a\u015fa\u011f\u0131daki e\u015fitlik bulunur:<\/p>\n

\"formul2\"<\/p>\n

N\u00d6TR HATTI BULUNAN YILDIZ BA\u011eLI \u015eEBEKEN\u0130N ANAL\u0130Z\u0130<\/strong><\/h4>\n

\"res2\"<\/p>\n

ZhN<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>N\u00f6tr hatt\u0131n\u0131n empedans\u0131<\/p>\n

IN<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/sub>N\u00f6tr hatt\u0131 ak\u0131m\u0131<\/p>\n

Bu ba\u011flant\u0131 \u015feklinde de benzer analizleri yapmak m\u00fcmk\u00fcnd\u00fcr ama \u00f6ncelikle Thevenin e\u015fde\u011fer devresini bulmam\u0131z laz\u0131m.<\/p>\n

Thevenin e\u015fde\u011fer devresi i\u00e7in iki ad\u0131m vard\u0131r: De\u011ferleri bulunmak istenen devre eleman\u0131 devreden \u00e7\u0131kar\u0131l\u0131r ve o noktalar a\u00e7\u0131k devre olarak b\u0131rak\u0131l\u0131r. Bu \u015fekildeyken devre analiz edilerek ilk ad\u0131mda Thevenin gerlim kayna\u011f\u0131 (UTH<\/sub>) bulunur. \u0130kinci ad\u0131mda ise yine devredeki t\u00fcm gerilim kaynaklar\u0131 k\u0131sadevre edilir ve devrenin toplam empedans\u0131 (ZTH<\/sub>) bulunur.<\/p>\n

Amac\u0131m\u0131z n\u00f6tr hatt\u0131ndan ge\u00e7en ak\u0131m\u0131n ak\u0131m ve gerilim de\u011ferlerini bulmak oldu\u011fundan Thevenin e\u015fde\u011fer devresini bulurken n\u00f6tr hatt\u0131 empedans\u0131n\u0131 devreden \u00e7\u0131kar\u0131p bu hatt\u0131 a\u00e7\u0131k devre olarak b\u0131rak\u0131r\u0131z.<\/p>\n

\"res3\"<\/p>\n

Bu \u015fekliyle devremiz, ilk b\u00f6l\u00fcmde ayr\u0131nt\u0131lar\u0131 verilen \u201cN\u00f6tr hatt\u0131 bulunmayan y\u0131ld\u0131z ba\u011fl\u0131 \u015febeke\u201d olur ve burada bulunan ba\u011flant\u0131lar kullan\u0131labilir. Aramakta oldu\u011fumuz Uab<\/sub> gerilimi \u201cn\u00f6tr hatt\u0131 olmayan y\u0131ld\u0131z ba\u011fl\u0131 \u015febeke\u201ddeki UN<\/sub> (5) ile ayn\u0131 oldu\u011fundan a\u015fa\u011f\u0131daki ba\u011flant\u0131y\u0131 yazabiliriz.<\/p>\n

\"formul3\"<\/p>\n

Thevenin empedans\u0131n\u0131 bulurken, gerilim kaynaklar\u0131n\u0131 k\u0131sadevre edince a\u015fa\u011f\u0131daki devre olu\u015fur.<\/p>\n

\"res4\"<\/p>\n

Bu devreyi analiz edince Thevenin empedans\u0131\u00a0\u00a0 ZTH <\/sub>= ZL1<\/sub> \/\/ ZL2<\/sub> \/\/ ZL3 <\/sub>i\u015flemiyle<\/p>\n

\"formul4\"<\/p>\n

e\u015fitli\u011fini kurabiliriz.<\/p>\n

Sonu\u00e7ta, Thevenin E\u015fde\u011fer devremiz<\/p>\n

\"res5\"<\/p>\n

halini al\u0131r ve ortaya \u00e7\u0131kan bu basit devre ile hem UN<\/sub> hem de IN<\/sub> de\u011ferlerini bulmak m\u00fcmk\u00fcnd\u00fcr.<\/p>\n

\"formul5\"<\/p>\n

Bu ifadelerdeki TH e\u015fde\u011ferleri yerine yukar\u0131da anlatt\u0131\u011f\u0131m\u0131z kar\u015f\u0131l\u0131klar\u0131n\u0131 yazar ve gerekli sadele\u015ftirmeleri yaparsak<\/p>\n

\"formul6\"<\/p>\n

 <\/p>\n

ba\u011flant\u0131s\u0131na ula\u015f\u0131r\u0131z.<\/p>\n

Zaten bu ba\u011flant\u0131da n\u00f6tr hatt\u0131n\u0131 a\u00e7\u0131k devre yaparsak (ki bu durumda devremiz n\u00f6tr hatt\u0131 bulunmayan y\u0131ld\u0131z ba\u011fl\u0131 \u015febekeye d\u00f6n\u00fc\u015f\u00fcr) ZN<\/sub> sonsuz (\u221e) olur ve 1\/ZN<\/sub> 0 olur ve b\u00f6ylece ifademiz n\u00f6tr hatt\u0131 bulunmayan y\u0131ld\u0131z ba\u011fl\u0131 \u015febekede buldu\u011fumuz UN<\/sub> ba\u011flant\u0131s\u0131yla ayn\u0131 olur. Benzer \u015fekilde bazen n\u00f6tr hatt\u0131n\u0131n empedans\u0131n\u0131 ihmal etmeyi tercih edebiliriz. Bu durumda ZN<\/sub> s\u0131f\u0131r (0) olur ve 1\/ZN<\/sub> tan\u0131ms\u0131z olur. Bu noktada UN<\/sub> =0 olacakt\u0131r ve IN<\/sub> i\u00e7in de Thevenin e\u015fde\u011fer devresindeki form\u00fclleri kullanmak daha iyi olur.<\/p>\n

\u00a0<\/strong><\/p>\n

MILLMAN TEOREM\u0130<\/strong><\/h4>\n

N\u00f6tr hatt\u0131 olan yada olmayan \u015febekelerin analizini yaparken Millman Teoreminden bahsetmemek eksiklik olur.<\/p>\n

\"res6\"<\/p>\n

Millman Teoremi der ki, yukar\u0131daki devredeki gibi, e\u011fer n say\u0131da paralel halde ba\u011flanm\u0131\u015f gerilim kayna\u011f\u0131 ve empedans varsa UN<\/sub> gerilimini a\u015fa\u011f\u0131daki ifadeyle bulmak m\u00fcmk\u00fcnd\u00fcr.<\/p>\n

\"formul7\"<\/p>\n

Millman teoreminin bu ba\u011flant\u0131s\u0131n\u0131 n\u00f6tr ba\u011flant\u0131s\u0131 bulunmayan y\u0131ld\u0131z ba\u011fl\u0131 \u015febekeye<\/u><\/em><\/strong> uygularsak \u00e7ok kolayca<\/p>\n

\"formul8\"<\/p>\n

ba\u011flant\u0131s\u0131na ula\u015f\u0131r\u0131z. N\u00f6tr ba\u011flant\u0131s\u0131 bulunan y\u0131ld\u0131z ba\u011fl\u0131 \u015febekeye <\/u><\/em><\/strong>uygularken ise \u015f\u00f6yle bir kolayl\u0131k yapal\u0131m: N\u00f6tr hatt\u0131n\u0131 4. Kol olarak d\u00fc\u015f\u00fcnelim ama gerilim de\u011ferini s\u0131f\u0131r (0) kabul edelim.<\/p>\n

\"formul9\"<\/p>\n

U4<\/sub>=0 ve Z4<\/sub>=ZN<\/sub>\u00a0 <\/sub>oldu\u011fundan<\/p>\n

\"formul10\"<\/p>\n

olur ki n\u00f6tr hatt\u0131 bulunan y\u0131ld\u0131z ba\u011fl\u0131 \u015febeke analizindeki ba\u011flant\u0131ya ula\u015f\u0131l\u0131r.<\/p>\n","protected":false},"excerpt":{"rendered":"

N\u00d6TR HATTI BULUNMAYAN YILDIZ BA\u011eLI \u015eEBEKEN\u0130N ANAL\u0130Z\u0130   ZL1, ZL2, ZL3\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 L1, L2 ve L3 fazlar\u0131n\u0131n toplam empedanslar\u0131 ZhL1 , ZhL2 , ZhL3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 L1, L2, ve L3 hatlar\u0131n\u0131n (besleme kablolar\u0131n\u0131n) empedanslar\u0131 ZYL1 , ZYL2 , ZYL3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 L1, L2, ve L3 hatlar\u0131ndan beslenen y\u00fcklerin empedanslar\u0131 Uo \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Toprak gerilimi, 0 V UN \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0… Dengesiz \u00dc\u00e7 Fazl\u0131 Sistemler<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":3567,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"neve_meta_sidebar":"","neve_meta_container":"","neve_meta_enable_content_width":"","neve_meta_content_width":0,"neve_meta_title_alignment":"","neve_meta_author_avatar":"","neve_post_elements_order":"","neve_meta_disable_header":"","neve_meta_disable_footer":"","neve_meta_disable_title":"","_themeisle_gutenberg_block_has_review":false,"footnotes":""},"categories":[5],"tags":[72,44,73,74,75,76,77,78],"class_list":["post-1739","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-elektrik-tesisat","tag-dengesiz-yuk","tag-elektrik","tag-millman-teoremi","tag-notr-hatti-akimi","tag-notr-hatti-bulunan-sebeke","tag-notr-hatti-olmayan-sebeke","tag-notr-noktasi-gerilimi","tag-uc-fazli-sebeke-analizi"],"_links":{"self":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/posts\/1739","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/comments?post=1739"}],"version-history":[{"count":0,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/posts\/1739\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/"}],"wp:attachment":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/media?parent=1739"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/categories?post=1739"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/tags?post=1739"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}