{"id":1901,"date":"2018-02-24T16:59:15","date_gmt":"2018-02-24T13:59:15","guid":{"rendered":"http:\/\/mekanikelektriktesisat.com\/?p=1901"},"modified":"2018-02-24T16:59:15","modified_gmt":"2018-02-24T13:59:15","slug":"test-pompasi","status":"publish","type":"post","link":"https:\/\/benga.pro\/index.php\/2018\/02\/24\/test-pompasi\/","title":{"rendered":"Bas\u0131nc\u0131 artt\u0131rmak i\u00e7in ne kadar su ekleyelim?"},"content":{"rendered":"

Devam eden y\u00fcksek katl\u0131 bir ofis binas\u0131 \u015fantiyemiz var. Bu binan\u0131n bir kat\u0131nda sprinkler tesisat\u0131n\u0131 14 bara getirip test etmemiz gerekiyordu. Hatt\u0131n dolumunu hidroforla sadece 4-5 bara kadar yapabiliyorduk, haliyle 14 bara y\u00fckseltilmesi i\u015fi test pompas\u0131na kal\u0131yordu. Elimizdeki elektrikli test pompas\u0131 ar\u0131zalan\u0131nca :<\/p>\n

-“Elle \u00e7al\u0131\u015fan test pompas\u0131 kullan\u0131n, eskiden elektrikli test pompas\u0131 m\u0131 vard\u0131?” demi\u015f bulundum.<\/p>\n

-“\u015eefim o kadar suyu elle basa basa bitiremeyiz” dedi formenimiz.<\/p>\n

-“Ne olacak ? Zaten hidrofor yar\u0131s\u0131na kadar bas\u0131n\u00e7land\u0131r\u0131yor, biz sadece 14 bara y\u00fckseltece\u011fiz, su s\u0131k\u0131\u015fan bir madde olmad\u0131\u011f\u0131na ve hacmimiz de sabit oldu\u011funa g\u00f6re gitse gitse az\u0131c\u0131k su gider” dedim.<\/p>\n

\"Manuel<\/p>\n

Bizim sekt\u00f6rde s\u0131v\u0131lar\u0131n, gazlar\u0131n s\u0131k\u0131\u015fmas\u0131 konusuna pek rastlamay\u0131z. Daha \u00e7ok hidrolikle, pn\u00f6matikle ilgili alanlarda kar\u015f\u0131la\u015f\u0131lan bir konu oldu\u011funu san\u0131yorum. Ancak b\u00f6yle bir hadise olunca test pompas\u0131yla ne kadar su basmam\u0131z gerekti\u011fini nas\u0131l hesaplayaca\u011f\u0131m\u0131z\u0131 merak ettim.<\/p>\n

Biraz ara\u015ft\u0131r\u0131nca “Bulk Mod\u00fcl”\u00fc kavram\u0131 kar\u015f\u0131ma \u00e7\u0131kt\u0131. Bulk mod\u00fcl\u00fc, bir k\u00fctlenin bas\u0131n\u00e7 alt\u0131nda s\u0131k\u0131\u015fmas\u0131n\u0131n bir \u00f6l\u00e7\u00fcs\u00fc oluyor. Maddenin s\u0131k\u0131\u015fmaya kar\u015f\u0131 g\u00f6sterdi\u011fi direnci yani hacimde meydana gelen nispi azalmaya kar\u015f\u0131l\u0131k gelen bas\u0131nc\u0131 g\u00f6sterir. Birimi bas\u0131n\u00e7 birimi olup [Pa]d\u0131r. Bu de\u011fer maddeye has bir de\u011fer olup s\u0131v\u0131larda \u00e7ok y\u00fcksek bir de\u011ferken gazlarda daha d\u00fc\u015f\u00fck bir de\u011fer oluyor. Yani suyu s\u0131k\u0131\u015ft\u0131rmak i\u00e7in \u00e7ok y\u00fcksek bas\u0131n\u00e7 uygulamak gerekirken ayn\u0131 bas\u0131nc\u0131n 1\/10.000 ‘i havay\u0131 s\u0131k\u0131\u015ft\u0131rmak i\u00e7in yeterli oluyor. Bulk mod\u00fcl\u00fcn\u00fcn form\u00fcl\u00fc \u015fudur:<\/p>\n

\"BulkModulu1\"<\/p>\n

K      Bulk Mod\u00fcl\u00fc [Pa]<\/p>\n

dP      K\u00fctle \u00fczerindeki bas\u0131n\u00e7taki de\u011fi\u015fimi [Pa, N\/m2<\/sup>]<\/p>\n

P0<\/sub>      K\u00fctle \u00fczerindeki ilk bas\u0131n\u00e7 de\u011feri [Pa, N\/m2<\/sup>]<\/p>\n

P1<\/sub>      K\u00fctle \u00fczerindeki son bas\u0131n\u00e7 de\u011feri [Pa, N\/m2<\/sup>]<\/p>\n

dV      K\u00fctlenin hacimsel de\u011fi\u015fimi [m3<\/sup>]<\/p>\n

V<\/span>0<\/sub>      K\u00fctlenin ilk hacmi [m3<\/sup>]<\/p>\n

V1<\/sub>      K\u00fctlenin son hacmi [m3<\/sup>]<\/p>\n

Bulk mod\u00fcl\u00fc alternatif olarak \u015fu \u015fekilde de form\u00fclize edilebilir:<\/p>\n

\"BulkModulu2\"<\/p>\n

 <\/p>\n

d\u03c1 <\/i>     K\u00fctlenin yo\u011funlu\u011funun de\u011fi\u015fimi [kg\/m3<\/sup>]<\/p>\n

\u03c10<\/sub>     K\u00fctlenin ilk yo\u011funlu\u011fu [kg\/m3<\/sup>]<\/p>\n

\u03c11<\/sub>      K\u00fctlenin son yo\u011funlu\u011fu [kg\/m3<\/sup>]<\/p>\n

m0<\/sub> ve  m1<\/sub> [kg] cinsinden ilk ve son k\u00fctle de\u011feri olmak \u00fczere  olmak \u00fczere, ba\u011f\u0131nt\u0131m\u0131z \u015fu hale gelir:<\/p>\n

\"BulkModulu4\"<\/p>\n

Bizim sistemimizde kattaki borunun hacmi sabit oldu\u011fundan (V0<\/span>=V1<\/sub> ), ba\u011f\u0131nt\u0131m\u0131z<\/p>\n

\"BulkModulu5\"<\/p>\n

halini al\u0131r.<\/p>\n

Kattaki borular\u0131n hacimlerinini hesaplad\u0131\u011f\u0131m\u0131zda a\u015fa\u011f\u0131 yukar\u0131 1m3<\/sup> hacmimiz oldu\u011funu g\u00f6rd\u00fck. Bu da 1000kg su demekti. Hatt\u0131m\u0131z\u0131 4 bardan 14 bara bas\u0131n\u00e7land\u0131rmay\u0131 planl\u0131yoruz. Suyun bulk mod\u00fcl\u00fcn\u00fcn 2,35×109<\/sup> Pa oldu\u011funu da biliyoruz. Bu de\u011ferleri yukar\u0131daki form\u00fclde yerine koyunca<\/p>\n

\"BulkModulu6\"<\/p>\n

de\u011ferine ula\u015f\u0131r\u0131z. Yani sistemimize 425 gram<\/strong> a\u011f\u0131rl\u0131\u011f\u0131nda sadece 2 bardak su eklesek 4 bardan 14 bara sistemimizi bas\u0131n\u00e7land\u0131raca\u011f\u0131z.<\/strong> Yani elle \u00e7al\u0131\u015fan test pompas\u0131n\u0131 kullanmak hi\u00e7 de yorucu olmayacak…. gibi g\u00f6r\u00fcn\u00fcyor.<\/p>\n

Ama pratikte i\u015fler farkl\u0131 y\u00fcr\u00fcyor. Hi\u00e7bir zaman 2 bardak suyla sistemin bas\u0131n\u00e7land\u0131r\u0131ld\u0131\u011f\u0131n\u0131 g\u00f6rmemiz m\u00fcmk\u00fcn de\u011fil. \u00c7\u00fcnk\u00fc bu t\u00fcr sistemlerin i\u00e7inde kayda de\u011fer miktarda hava bulunur. \u00d6zellikle sprinkler sistemlerinde sistem dolumu yaparken hava al\u0131nacak noktalar olmad\u0131\u011f\u0131ndan sistem i\u00e7inde \u00e7ok miktarda hava kalabilir.<\/p>\n

Bizim sistemimizde de \u00e7ok de\u011fil %10 oran\u0131nda hava oldu\u011funu varsaysak ve hesab\u0131m\u0131z\u0131 ona g\u00f6re tekrar yapsak bakal\u0131m sonu\u00e7 ne \u00e7\u0131kacak? B\u00f6ylece iyi s\u0131k\u0131\u015fabilen bir madde olan havan\u0131n sistemimize yapt\u0131\u011f\u0131 etkiyi de alg\u0131layabiliriz.<\/p>\n

Sadece sistemin i\u00e7indeki havay\u0131 ele alarak hesap yapal\u0131m.<\/p>\n

Sistemimizin %10u hava oldu\u011funa g\u00f6re 0,1m3<\/sup> havam\u0131z var. Sistemdeki hava miktar\u0131 de\u011fi\u015fmedi\u011finden m0<\/sub>=m1<\/sub>   olacakt\u0131r. (Havan\u0131n bulk mod\u00fcl\u00fc 1,01×105<\/sup> Pa)<\/p>\n

\"BulkModulu7\"<\/p>\n

Yani sistemin i\u00e7indeki 100litre hacmindeki hava s\u0131k\u0131\u015f\u0131p 9,1 litreye kadar d\u00fc\u015f\u00fcyor. Bu durumda yakla\u015f\u0131k 90litre suyu test pompas\u0131yla basmam\u0131z gerekiyor. Manuel test pompas\u0131n\u0131n teknik detaylar\u0131n\u0131 inceleyince ortalama b\u00fcy\u00fckl\u00fckteki bir test pompas\u0131n\u0131n bir kol hareketiyle ortalama 45ml su bast\u0131\u011f\u0131n\u0131 g\u00f6rd\u00fcm. Bu da yakla\u015f\u0131k 2000 kol hareketi demektir  ki i\u015fte bu yorucu olacakt\u0131r.<\/p>\n

Yani formenimiz hakl\u0131 \u00e7\u0131km\u0131\u015ft\u0131. Bu olay teorik ile pratik bilgi aras\u0131ndaki fark\u0131 g\u00f6steren \u00e7arp\u0131c\u0131 bir hadise olmu\u015ftu.<\/p>\n

Ger\u00e7ekte testi yaparken de bu miktardan biraz daha az su gitti\u011fini s\u00f6yleyebilirim. Demek ki sistemin i\u00e7indeki hava daha azm\u0131\u015f. Neticede, fiyat\u0131 biraz pahal\u0131 ve s\u0131k ar\u0131zalan\u0131yor ama elektrikli test pompas\u0131 her \u015fantiye i\u00e7in gerekli g\u00f6r\u00fcn\u00fcyor.<\/p>\n

\"Elektrikli<\/p>\n

Kaynaklar<\/p>\n

    \n
  1. Bulk Modulus and Fluid Elasticity<\/a><\/li>\n
  2. Rothenberger Testing Pump<\/a><\/li>\n<\/ol>\n

     <\/p>\n","protected":false},"excerpt":{"rendered":"

    Devam eden y\u00fcksek katl\u0131 bir ofis binas\u0131 \u015fantiyemiz var. Bu binan\u0131n bir kat\u0131nda sprinkler tesisat\u0131n\u0131 14 bara getirip test etmemiz gerekiyordu. Hatt\u0131n dolumunu hidroforla sadece 4-5 bara kadar yapabiliyorduk, haliyle 14 bara y\u00fckseltilmesi i\u015fi test pompas\u0131na kal\u0131yordu. Elimizdeki elektrikli test pompas\u0131 ar\u0131zalan\u0131nca : -“Elle \u00e7al\u0131\u015fan test pompas\u0131 kullan\u0131n, eskiden elektrikli test pompas\u0131 m\u0131 vard\u0131?” demi\u015f… Bas\u0131nc\u0131 artt\u0131rmak i\u00e7in ne kadar su ekleyelim?<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":3571,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"neve_meta_sidebar":"","neve_meta_container":"","neve_meta_enable_content_width":"","neve_meta_content_width":0,"neve_meta_title_alignment":"","neve_meta_author_avatar":"","neve_post_elements_order":"","neve_meta_disable_header":"","neve_meta_disable_footer":"","neve_meta_disable_title":"","_themeisle_gutenberg_block_has_review":false,"footnotes":""},"categories":[7],"tags":[144,145,146,147,148,149],"class_list":["post-1901","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mekanik-tesisat","tag-basinclandirmak-icin-ne-kadar-su-eklemek-lazim","tag-bulk-modulu","tag-elektrikli-test-pompasi","tag-sikimazlik","tag-test-pompasi","tag-test-pompasina-konacak-su-miktari"],"_links":{"self":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/posts\/1901","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/comments?post=1901"}],"version-history":[{"count":0,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/posts\/1901\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/"}],"wp:attachment":[{"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/media?parent=1901"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/categories?post=1901"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/benga.pro\/index.php\/wp-json\/wp\/v2\/tags?post=1901"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}